1. find in standard form, the equation of the line that is perpendicular to y=-9x+1 and passes through (10,2)

2.wr ite down the equation of the line that is perpendicular to the y axis and passes through (-5,1)

3.write down the equation of a line parallel to the y axis that passes through(-7,4)

4.every point on a particular line is shifted 2 units down. the resulting line has equaiton y=3x-5. what is the equation of the original line?

xxJenny1213xx May 1, 2020

#1**+1 **

1. find in standard form, the equation of the line that is perpendicular to y=-9x+1 and passes through (10,2)

The slope of the given line = -9

The slope of a perpendicular line =1/9

So we have

y = (1/9) ( x - 10) + 2 multiply through by 9

9y = x - 10 + 18

9y = 1x + 8

1x - 9y = - 8 or 1x - 9y + 8 = 0

CPhill May 1, 2020

#2**+1 **

2. Write down the equation of the line that is perpendicular to the y axis and passes through (-5,1)

The equation is

y = 1

CPhill May 1, 2020

#3**+1 **

3. Write down the equation of a line parallel to the y axis that passes through(-7,4)

The equation is

x = -7

CPhill May 1, 2020

#4**+4 **

4) -5 means that the line 3x is shifted down 5. This includes the two points. -5+2 = -3/

y= 3x-3

Ask if you don't understand anything

edit: YES I BEAT CPHILL

hugomimihu May 1, 2020

#7**+3 **

Haha thanks but we both know you and melody are much smarter than the rest of us generic members lol

hugomimihu
May 1, 2020