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avatar+238 

1. find in standard form, the equation of the line that is perpendicular to y=-9x+1 and passes through (10,2)

2.wr ite down the equation of the line that is perpendicular to the y axis and passes through (-5,1)

3.write down the equation of a line parallel to the y axis that passes through(-7,4)

4.every point on a particular line is shifted 2 units down. the resulting line has equaiton y=3x-5. what is the equation of the original line?

 May 1, 2020
 #1
avatar+111360 
+1

1. find in standard form, the equation of the line that is perpendicular to y=-9x+1 and passes through (10,2)

 

The slope  of the given line  = -9

 

The slope of a perpendicular line  =1/9

 

So we have

 

y = (1/9) ( x - 10) + 2      multiply through by 9

 

9y  = x - 10 + 18

 

9y  = 1x + 8

 

1x - 9y = - 8   or    1x - 9y + 8  = 0

 

 

cool cool cool

 May 1, 2020
 #2
avatar+111360 
+1

2. Write down the equation of the line that is perpendicular to the y axis and passes through (-5,1)

 

The  equation  is

 

y  = 1

 

cool cool cool

 May 1, 2020
 #3
avatar+111360 
+1

3. Write down the equation of a line parallel to the y axis that passes through(-7,4)

 

The equation is

 

x   = -7

 

cool cool cool

 May 1, 2020
 #4
avatar+1458 
+4

4) -5 means that the line 3x is shifted down 5. This includes the two points. -5+2 = -3/

 

y= 3x-3

 

Ask if you don't understand anything
 

 

edit: YES I BEAT CPHILL 

 May 1, 2020
edited by hugomimihu  May 1, 2020
 #6
avatar+111360 
0

LOL!!!!...you guys are tough to keep up with   !!!!

 

 

cool cool cool

CPhill  May 1, 2020
 #7
avatar+1458 
+3

Haha thanks but we both know you and melody are much smarter than the rest of us generic members lol

hugomimihu  May 1, 2020
 #5
avatar+111360 
+1

4.every point on a particular line is shifted 2 units down. the resulting line has equaiton y=3x-5. what is the equation of the original line?

 

The equation of the original  line  must have been :

 

y =  3x - 5 + 2    =   3x - 3

 

 

cool cool cool

 May 1, 2020
 #8
avatar+238 
+1

thank you!

xxJenny1213xx  May 1, 2020

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