+614 1. find in standard form, the equation of the line that is perpendicular to y=-9x+1 and passes through (10,2)
2.wr ite down the equation of the line that is perpendicular to the y axis and passes through (-5,1)
3.write down the equation of a line parallel to the y axis that passes through(-7,4)
4.every point on a particular line is shifted 2 units down. the resulting line has equaiton y=3x-5. what is the equation of the original line?
+128475 1. find in standard form, the equation of the line that is perpendicular to y=-9x+1 and passes through (10,2)
The slope of the given line = -9
The slope of a perpendicular line =1/9
So we have
y = (1/9) ( x - 10) + 2 multiply through by 9
9y = x - 10 + 18
9y = 1x + 8
1x - 9y = - 8 or 1x - 9y + 8 = 0
+128475 2. Write down the equation of the line that is perpendicular to the y axis and passes through (-5,1)
The equation is
y = 1
+128475 3. Write down the equation of a line parallel to the y axis that passes through(-7,4)
The equation is
x = -7
+1005 4) -5 means that the line 3x is shifted down 5. This includes the two points. -5+2 = -3/
y= 3x-3
Ask if you don't understand anything
edit: YES I BEAT CPHILL
+1005 Haha thanks but we both know you and melody are much smarter than the rest of us generic members lol
