Find the value of if the graph of passes through the point and is parallel to the graph of

Scythgirl Jun 6, 2021

#1**0 **

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Melody Jun 6, 2021

#2**+2 **

\(x+3y=-5 \)

\(3y=-x-5\)

\(y=-\frac{1}{3}x-\frac{5}{3}\)

so the slope of the line that is parallel to \(x+3y=-5\) is \(-\frac{1}{3}\)

Using point-slope form, we have:

\(y+7=-\frac{1}{3}(x-2)\)

\(y=-\frac{1}{3}x-\frac{19}{3}\)

\(3x+3y=-19\)

then, you multiply A and B by -3/19. obviously, B-A will equal 0.

JP

JKP1234567890 Jun 6, 2021