If the quadratic x^2+6mx+m has exactly one real root, find the positive value of m.
x^2 + 6mx + m = 0
If this has one real root the discriminant is 0
So...
(6m)^2 - 4m = 0
36m^2 - 4m = 0
9m^2 - m = 0 factor
m (9m - 1) = 0
Setting each factor to 0 and solving for m produces
m = 0 or m = 1/9
+80 
