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Suppose g is a linear function such that g(3.5) = 5.1. If the slope of g is -2.2, what is g(6.9)? (Round your answer to two decimal places.)

If someone answers this, can I please get an explanation. 

 Mar 29, 2020
 #1
avatar+23710 
+2

Linear    so  y = mx+ b     m is given as -2.2

                    y = -2.2 x + b     when x = 3.5     y = 5.1    sub that in

                   5.1 = -2.2 (3.5)  + b         so b = 12.8  

 

 

y = -2.2 x   + 12.8        now put in x = 6.9    to find the value of  'y'   

 Mar 29, 2020
 #2
avatar+115 
+1

I appreciate you! 

Shaezy  Apr 1, 2020
 #3
avatar+115 
0

Suppose g is a linear function such that g(1.2) = 3.3 and g(-3) = 7.2. Find the equation for g. (Use x for the variable. Round equation parameters to two decimal places.)

 

On this question, I did the y2-y1/x2-x1 and got -2.17 rounded. that wasnt correct. It is almost like the question you helped me with but a little different. Care to help me with this one? 

Shaezy  Apr 1, 2020
 #4
avatar+109527 
+1

Suppose g is a linear function such that g(1.2) = 3.3 and g(-3) = 7.2. Find the equation for g. (Use x for the variable. Round equation parameters to two decimal places.)

 

7.2-3.3=3.9

-3- -1.2 = -1.8

 

gradient = 3.9/-1.8 = -13/6  = -2.1666666666666667  = -2.17

 

g(x)=mx+b

g(x)=-2.17x+b

(1.2, 3.3)

3.3= -2.17*1.2 +b

b=3.3 + (-13/6)*1.2 = 0.7

 

g(x)= -2.17x + 0.7

Melody  Apr 5, 2020
edited by Melody  Apr 5, 2020

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