+115 Suppose g is a linear function such that g(3.5) = 5.1. If the slope of g is -2.2, what is g(6.9)? (Round your answer to two decimal places.)
If someone answers this, can I please get an explanation.
+37146 Linear so y = mx+ b m is given as -2.2
y = -2.2 x + b when x = 3.5 y = 5.1 sub that in
5.1 = -2.2 (3.5) + b so b = 12.8
y = -2.2 x + 12.8 now put in x = 6.9 to find the value of 'y'
+115 Suppose g is a linear function such that g(1.2) = 3.3 and g(-3) = 7.2. Find the equation for g. (Use x for the variable. Round equation parameters to two decimal places.)
On this question, I did the y2-y1/x2-x1 and got -2.17 rounded. that wasnt correct. It is almost like the question you helped me with but a little different. Care to help me with this one?
+118667 Suppose g is a linear function such that g(1.2) = 3.3 and g(-3) = 7.2. Find the equation for g. (Use x for the variable. Round equation parameters to two decimal places.)
7.2-3.3=3.9
-3- -1.2 = -1.8
gradient = 3.9/-1.8 = -13/6 = -2.1666666666666667 = -2.17
g(x)=mx+b
g(x)=-2.17x+b
(1.2, 3.3)
3.3= -2.17*1.2 +b
b=3.3 + (-13/6)*1.2 = 0.7
g(x)= -2.17x + 0.7
