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Please help! Thanks!!

Guest Nov 28, 2018
 #1
avatar+789 
+6

1) From the diagram, we know the following: Angle B = Angle M = 42, Angle C = Angle N = 90, and Side BC = 4 is half of Side NM  = 8. 

Since all triangles have an interior measure of 180 degrees, if two triangles have the same measures for two angles, then the third angles must have the same measure, meaning they are similar. We also know that Triangle LMN is 2: 1 ration in side length compared to Triangle ABC. Therefore the area of Triangle LMN is 4 times larger than the area of ABC. (This is not needed in the problem though)

 

The answer is A, similar by AA. 

PartialMathematician  Nov 28, 2018
 #2
avatar+92856 
+2

First one

ΔABC is similar to ΔLMN by AA congruency

 

Second one

This is the absolute value funtion shifted 1 unit to the left and 2 units down

 

The function is    f(x) = l x + 1 l - 2  ⇒  "P"

 

 

cool cool cool

CPhill  Nov 28, 2018
 #3
avatar+789 
+6

3) Multiply the following polynomial: \((x-7)(3x^2+8)\). We do the same thing we do with a normal polynomial, we use FOIL (multiply each term). If we multiply \(x\) with \((3x^2+8)\), we get \(3x^3 + 8x\). Similarly, if we multiply \(-7\) with \((3x^2+8)\), we get \(-21x^2-56\). If we add our results, we get \(3x^3 + 8x - 21x^2 - 56 = \boxed{3x^3 - 21x^2 + 8x -56}\)

 

Hope this helps,

- PM

PartialMathematician  Nov 28, 2018
 #4
avatar+92856 
+1

Last one

 

f(x - 3)    shifts f(x) to the RIGHT by 3 units

 

 

cool cool cool

CPhill  Nov 28, 2018
 #5
avatar
0

Thank you for your help! Sorry for late response!

Guest Nov 28, 2018
 #6
avatar+92856 
0

No prob....I  just answered the last one  a little while ago

 

 

cool cool cool

CPhill  Nov 28, 2018

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