The equation 
describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest tenth.
+33615 Set y = 0 and solve the resulting equation for t. There will be two values; choose the only sensible one.
+30 I remember seeing this problem in Alcumus, or maybe a similar variation of it. However, the solution is pretty simple.
set y = 0, since we are trying to find out when the ball hits the ground, and when that happens, Y = 0.
This looks like a quadratic formula!
\(0 = -16t^2 + 26t + 105\)
Then, simply solve for this quadratic. There will be two answers, but one of them is negative, so choose the postitve answer.
\(\frac{-26 +\sqrt{26^2 - 4(-16)(105)} }{2(-16)}\)
That should be the postive answer. Sorry, it's a little messy. Solve this equation and the answer shall be the final answer!
Hope this helps!
