Given the circle center at O, OT ias perpendicular to PT, If arcNBT is a semi circle and minor arcNB is 60 degrees what is angle APT?
Extend line from O to N angle BON = AOT = 60
APT is in a triangle witht wo other angles 90 and 60 degrees
APT = 180 - 60- 90 = ......
I'm gonna attempt to answer Guest's question: What is the angle APM?
∠BON = ∠AOT = 60º ∠APT = 30º
∠BOT = ∠AON= 120º
Radius TO = 1
Diameter TN = 2
PT = TO / tan(30º)
∠NPT = tanarc( TN / PT ) ≈ 49.107º
∠AMP ≈ 19.107º
(1st question is for 5th graders and the second one for college students.)