please help!

\(\frac{x+4}{x+5} = \frac{x-5}{2x}\)

 

2x(x + 4) = (x - 5)(x + 5)

2x² + 8x = x² - 25

x² + 8x + 25 = 0

 

\(x = {-8 \pm \sqrt{8^2-4(1)(25)} \over 2(1)}\)

\(x = {-8 \pm \sqrt{-36} \over 2}\)

\(x = {-8 \pm 6i \over 2}\)

\(x = -4 \pm 3i\)

 

Which means the solutions are: 

x = -4 + 3i

x = -4 - 3i