+0  
 
+1
106
6
avatar+604 

 Find all numbers such that the square of the number is 48 more than double the number. If you find more than one, then list all the numbers you find in increasing order, separated by commas.

gueesstt  Apr 9, 2018
 #1
avatar+26829 
+1

Let the number be x.  Then  x^2 = 2x + 48.  This can be rearranged as:  x^2 - 2x - 48 = 0

 

In turn this can be factored as (x + 6)(x - 8) = 0, so the two possible solutions are x = -6 and x = 8.

Alan  Apr 9, 2018
 #3
avatar+428 
0

agreed man

jakesplace  Apr 9, 2018
 #6
avatar+604 
0

Than you so much!

gueesstt  Apr 9, 2018
 #2
avatar+428 
-1

Let the number be x.  Then  x^2 = 2x + 48.  This can be rearranged as:  x^2 - 2x - 48 = 0

 

In turn this can be factored as (x + 6)(x - 8) = 0, so the two possible solutions are x = -6 and x = 8.

jakesplace  Apr 9, 2018
 #4
avatar+604 
0

Yes that is correct, thank you!

gueesstt  Apr 9, 2018
 #5
avatar+428 
0

np dude

jakesplace  Apr 9, 2018

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