Find all numbers such that the square of the number is 48 more than double the number. If you find more than one, then list all the numbers you find in increasing order, separated by commas.

gueesstt
Apr 9, 2018

#1**+1 **

Let the number be x. Then x^2 = 2x + 48. This can be rearranged as: x^2 - 2x - 48 = 0

In turn this can be factored as (x + 6)(x - 8) = 0, so the two possible solutions are x = -6 and x = 8.

Alan
Apr 9, 2018

#2**-1 **

Let the number be x. Then x^2 = 2x + 48. This can be rearranged as: x^2 - 2x - 48 = 0

In turn this can be factored as (x + 6)(x - 8) = 0, so the two possible solutions are x = -6 and x = 8.

jakesplace
Apr 9, 2018