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Here is the question:

And here is the answer: 

I understand till "There are 20 ways" but then, P(event does not occur), where did the (1/6)^3 come from??
Please help as fast as possible! Thank you.

 May 10, 2022
 #1
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anyone?

 May 11, 2022
 #2
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It is more confusing becasue some of what is written is WRONG.  

 

There are 20 ways that this can happen

and there are  6*6*6 = 216 different possible rolls     

              6 choices for the 1st roll, 6 for the second, 6 for the third = 6*6*6 different outcomes  (order definitely counts)

 

P(that it WILL happen ) =    \(\frac{20}{216}\)

 

P( that it  DOES NOT happen ) =   \(1-\frac{20}{216}\)

 

P( that it WILL NOT happen twice in a row  ) =  \((1-\frac{20}{216})^2\)

 

 

Does that make more sense? 

 May 11, 2022
 #3
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Yes, thank you!!

Guest May 11, 2022

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