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at a sports day the school pupils participated and in a conetst, which was made out of 3 courses : runing,bicycle riding and swiming. the leangth of the swiming cours course was 20% of the leangth of the riding course.the runing course leangth was 1/5 of the swiming course. the combined leangth of all of those 3 courses was 62km. what was the leangth of each course?

math
 Aug 23, 2014

Best Answer 

 #1
avatar+33657 
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Let r = length of riding course, s = length of swimming course and n = length of running course.

Then s = 0.2r and n = s/5 = 0.2r/5 so total length = r + 0.2r + 0.2r/5 = 1.24r

This equals 62km so 1.24r = 62;  r = 62/1.24 or:

r = 50 km

s = 0.2r = 10km

n = s/5 = 2km

 Aug 23, 2014
 #1
avatar+33657 
+10
Best Answer

Let r = length of riding course, s = length of swimming course and n = length of running course.

Then s = 0.2r and n = s/5 = 0.2r/5 so total length = r + 0.2r + 0.2r/5 = 1.24r

This equals 62km so 1.24r = 62;  r = 62/1.24 or:

r = 50 km

s = 0.2r = 10km

n = s/5 = 2km

Alan Aug 23, 2014

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