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Let

 

If the graph y=f(x) is continuous, find all possible values of n.

 Aug 7, 2019
edited by Guest  Aug 7, 2019
 #1
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At the x value of n, n^2+2 has to be equal to 2n+5 for the function to be continuous at x=n.

 

\(n^2+2=2n+5\)

\(n^2-2n-3=0\)

\((n-3)(n+1)=0\)

\(n=3, n=-1\)

 

The sum of all values of n is 3-1=2.

 Aug 8, 2019

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