Let

If the graph y=f(x) is continuous, find all possible values of n.

Guest Aug 7, 2019

edited by
Guest
Aug 7, 2019

#1**+3 **

At the x value of n, n^2+2 has to be equal to 2n+5 for the function to be continuous at x=n.

\(n^2+2=2n+5\)

\(n^2-2n-3=0\)

\((n-3)(n+1)=0\)

\(n=3, n=-1\)

The sum of all values of n is 3-1=**2**.

dgfgrafgdfge111 Aug 8, 2019