Let
If the graph y=f(x) is continuous, find all possible values of n.
+937 At the x value of n, n^2+2 has to be equal to 2n+5 for the function to be continuous at x=n.
\(n^2+2=2n+5\)
\(n^2-2n-3=0\)
\((n-3)(n+1)=0\)
\(n=3, n=-1\)
The sum of all values of n is 3-1=2.
