In the diagram above, the sides of △ABC are tangent to the inscribed circle with radius c and center O at points E,D and F where BD = a and DC = b.
Let ab > c^2 and P be the perimeter of △ABC. Find \(\dfrac{(ab - c^2)P}{ab(a + b)}\)
Oh, nevermind. I thought this was something else. I'm sorry.
