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If y= x^2+2x+8/x-4, at what value of x will there be a vertical asymptote?

 May 18, 2021
 #1
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Where the denominator approaches zero there will be a vertical asymtope.....

 May 18, 2021
 #2
avatar+115 
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Here is a tip before posting in this forum for an answer: 

 

Graph it out! https://www.desmos.com/calculator is a good graphing calc

 

Look at the graph, and it's easy. try it out!

 May 18, 2021

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