If y= x^2+2x+8/x-4, at what value of x will there be a vertical asymptote?
Where the denominator approaches zero there will be a vertical asymtope.....
Here is a tip before posting in this forum for an answer:
Graph it out! https://www.desmos.com/calculator is a good graphing calc
Look at the graph, and it's easy. try it out!
+36915 
