Please help

Is the 10kg objest being pulled up a 60 degree incline?  Or is the pulling force acting in a 60 degree direction (NOT horizontal) as the object is dragged along a flat surface?

I assume this is a pendulum bob held in equilibrium by a horizontal force, F.

The forces acting on the Bob are those of gravity (mg), the tension, T, in the string, and F.

Resolve forces horizontally and vertically.

Horizontal:  F = T*sin(60)

Vertical:       T*cos(60) = 10*g

Can you take it from here?

From the vertical component divide both sides by cos(60):  T = 10g/cos(60)

ut this into the horizontal component:  F = (10g/cos(60)) * sin(60) → 10g *tan(60)

Now tan(60) = sqrt(3)  so  F = 10*sqrt(3)*g   (g = 9.81 m/s^2)  

I would call this F = 98.1*sqrt(3) N.