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When three standard dice are tossed, the numbers a,b,c are obtained. Find the probability that (a-1)(b-1)(c-1)  not equal to 0

 

209/207 is sadly wrong...

 May 19, 2020
 #1
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I said 209/216

 May 19, 2020
 #2
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Oh oops, I realize............

 May 19, 2020
 #3
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For the product not to equal 0, each of the three dice must not be a 1.

So, the probability that a isn't a 1 is 5/6

the probability that b isn't a 1 is 5/6

and the probability that c isn't a 1 is 5/6.

 

Since these are independent, the final probability is 5/6 x 5/6 x 5/6  =  125/216.

 May 19, 2020

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