Please Help!

(b): 

Take a point (a,b)  on the graph of y=f(x), so b=f(a). Since $\left( 3a - 1, \frac{b}{2} \right)$ lies on the graph of y=g(x) we have that $\frac{b}{2} = g(3a - 1).$

Substituting b=f(a) we get $\frac{f(a)}{2} = g(3a - 1).$

In order to express g(x) in terms of f(x) we can let x = 3a-1 Then a=$\frac{x + 1}{3}$, so

                                                       $g(x) = \frac{f(a)}{2} = \frac{1}{2} f \left( \frac{x + 1}{3} \right).$

Sorry that I can't do the problems (a) and (c) because the LaTeX code is too complicated for drawing the diagram. I hope you understand

First, we observe that the graph of y=f(x) consists of line segments, connecting the points (-4, 4), (-1,0), (0,2),  and (4,-4).

So to plot the graph of y=g(x) we can apply the transformation  $(a,b) \to \left( 3a - 1, \frac{b}{2} \right)$ to each of these points, and then connect them. This gives us the points (-13,2), (-4,0), (-1,1), and (11,-2).  

 Hope this helps! 

I got it working.