How could I find the equation of the tangent line to the curve with equation y=(x^2-3)^5 at the point (2,1)?
+36916 The first derivative will give you the slope at x = 2 ( from the point 2,1)
10x (x^2-3)^4 when x = 2
10(2)(4-2)^4 = 20 = the slope at x = 2
y = mx + b
y = 20x + b for the point 2,1
1 = 20(2) + b b = -39
y = 20x - 39
Here is a graph to confirm:
https://www.desmos.com/calculator/eqlln3qpv9
