We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

Problem: A non-linear system consists of two functions: f(x) = x^2 + 2x + 1 and g(x) = 3 - x - x^2. 

A. Solve the system algebraically. (Hint: set the two functions equal to each other and solve the resulting function.) You should obtain a quadratic equation. Solve it either by factoring or using the quadratic formula. Give the x-values of the solution set, then evaluate the original function to find the corresponding y-values. Give the results as ordered pairs of exact values. 

B. Make a table of values for the functions. The table may be horizontal or vertical but it must have a minimum of five x-values and the corresponding function values showing each solution, one value lower, one value higher, and one between the two solutions. indiciate the solutions by marking the x-values and the corresponding function values that are equal.


—- Thanks to anyone who helps!

 Apr 7, 2019

Uhhhh....   You are given pretty explicit directions as to how to solve this.....did you try the directions?

 Apr 7, 2019

 x^2 + 2x + 1 = 3 - x - x^2.


2x^2 + 3x -2  = 0       Factor it......or use Qudartic Formula \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)     where a = 2  b = 3   c = -2


(2x -1)(x +2) = 0        means x = -2  or 1/2  

      now sub these values back in to either one of the original equations to find the corresponding 'y' values........

 Apr 7, 2019

28 Online Users