Problem: A non-linear system consists of two functions: f(x) = x^2 + 2x + 1 and g(x) = 3 - x - x^2.

A. Solve the system algebraically. (Hint: set the two functions equal to each other and solve the resulting function.) You should obtain a quadratic equation. Solve it either by factoring or using the quadratic formula. Give the x-values of the solution set, then evaluate the original function to find the corresponding y-values. Give the results as ordered pairs of exact values.

B. Make a table of values for the functions. The table may be horizontal or vertical but it must have a minimum of five x-values and the corresponding function values showing each solution, one value lower, one value higher, and one between the two solutions. indiciate the solutions by marking the x-values and the corresponding function values that are equal.

—- Thanks to anyone who helps!

lunarstrawberry Apr 7, 2019

#1**+1 **

Uhhhh.... You are given pretty explicit directions as to how to solve this.....did you try the directions?

ElectricPavlov Apr 7, 2019

#2**+1 **

x^2 + 2x + 1 = 3 - x - x^2.

2x^2 + 3x -2 = 0 Factor it......or use Qudartic Formula \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) where a = 2 b = 3 c = -2

(2x -1)(x +2) = 0 means x = -2 or 1/2

now sub these values back in to either one of the original equations to find the corresponding 'y' values........

ElectricPavlov Apr 7, 2019