The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 + xz2 + yz – 24. What is the value of x? What is the value of y?
Add 2 to both sides:
z = 3 or z^2+(7 z)/4 = 2
Add 49/64 to both sides:
z = 3 or z^2+(7 z)/4+49/64 = 177/64
Write the left hand side as a square:
z = 3 or (z+7/8)^2 = 177/64
Take the square root of both sides:
z = 3 or z+7/8 = sqrt(177)/8 or z+7/8 = -sqrt(177)/8
Subtract 7/8 from both sides:
z = 3 or z = sqrt(177)/8-7/8 or z+7/8 = -sqrt(177)/8
Subtract 7/8 from both sides:
Answer: |z = 3 or z = sqrt(177)/8-7/8 or z = -7/8-sqrt(177)/8
Substituting 3 into: –4z3 + xz2 + yz – 24
x, and y have infinite solutions such as x=1, 2, 3, 4.......... y=18, 16, 14, 12......Now you can see the patern.
P.S. I think you dreamed this one up yourself!!!!!!!.
