In a different plan for area codes, the first digit could be any number from 2 through 8, the second digit was either 4 ,5 , 6 7, and the third digit could be any number except 5 With this plan, how many different area codes are possible?
+23245 There are 7 choices for the first digit (2, 3, 4, 5, 6, 7, 8).
There are 4 choices for the second digit (4, 5, 6, 7)
There are 9 choices for the third digit (0, 1, 2, 3, 4, 6, 7, 8, 9).
Since these choices are independent, we need to multiply the three numbers: 7 x 4 x 9 to get the correct answer.
