Please help.

The solution of $8x+1\equiv 5\pmod{12}$ is $x\equiv a\pmod{m}$ for some positive integers $m\ge 2$ and $a<2$. Find $a+m$.

Hi ya'll, I got 17, because 5 can be a solution for x (actual solution is 3n+2 for some random integer n).

If you plug that in, you get

41 ≡ 5 (mod 12), which works because 41 (mod 12) = 5.

That means a=5 and m=12.

$12\ge 2$ and $5<12$.

5+12=17, so why is this wrong?  (I checked and it said it was wrong )