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The expression 6x^2 + 17x + 5 can be written in the form (Ax+1)(Bx+5) where A and B are integers. What is the value of AB?

 Jun 21, 2021

Best Answer 

 #1
avatar+148 
+1

when we expand (Ax+1)(Bx+5), we get -

 

ABx^2 + 5Ax + Bx + 5

 

we know that the coefficient of x^2 in the initial expression is 6, so therefore we know AB must be 6.

 

 

hope this helped! please correct me if i am wrong :)

 Jun 21, 2021
 #1
avatar+148 
+1
Best Answer

when we expand (Ax+1)(Bx+5), we get -

 

ABx^2 + 5Ax + Bx + 5

 

we know that the coefficient of x^2 in the initial expression is 6, so therefore we know AB must be 6.

 

 

hope this helped! please correct me if i am wrong :)

idyllic Jun 21, 2021

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