+130085 For f-1(-3) we have that either
2 - x = -3 or 2x - x^2 = -3
x = 5 x^2 - 2x - 3 = 0
not defined for 2 - x (x - 3) ( x + 1) = 0
x = 3 or x = -1
only the first value is defined for 2x - x^2
For f-1(0) we have that either
2 - x = 0 or 2x - x^2 = 0
x = 2- 0 x^2 - 2x = 0
x = 2 x(x - 2) = 0
not defined for 2 - x x = 0 or x = 2
only the second value is defined for 2x - x^2
For f-1(3) we have that either
2 - x = 3
x = 2 -3
x = -1
This is defined for 2 - x
So
f-1(-3) + f-1(0) + f-1(3) =
3 + 2 - 1 =
4
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