Two consecutive integers are represented by x and x+2. The sum of the reciprocals of the integers is 29/420. Show your work and algebraically determine the two integers.

Guest Jul 23, 2021

#1**+2 **

x and x +2 are NOT exactly consecutive integers......they are either consecutive ODD or EVEN integers

x and x+1** are** consecutive integers so I am not sure what your question means.....but if it is supposed to be x and x+1 then:

1/x + 1/(x+1) = 29/420 multiply both sides by x(x+1)

x+1 + x = 29/240 ( x^2 + x) now solve for 'x' then the other number is x+1

If your Q **IS** supposed to be x and x+2 then

1/x + 1/(x+2) = 29/240 multiply both sides by x(x+2)

x+2 + x = 29 / 240 ( x^2 + 2x) solve for x then the other number is x+2

Can you finish?

ElectricPavlov Jul 23, 2021

#1**+2 **

Best Answer

x and x +2 are NOT exactly consecutive integers......they are either consecutive ODD or EVEN integers

x and x+1** are** consecutive integers so I am not sure what your question means.....but if it is supposed to be x and x+1 then:

1/x + 1/(x+1) = 29/420 multiply both sides by x(x+1)

x+1 + x = 29/240 ( x^2 + x) now solve for 'x' then the other number is x+1

If your Q **IS** supposed to be x and x+2 then

1/x + 1/(x+2) = 29/240 multiply both sides by x(x+2)

x+2 + x = 29 / 240 ( x^2 + 2x) solve for x then the other number is x+2

Can you finish?

ElectricPavlov Jul 23, 2021