Please help

This is just a guess but I think it is -54

F = First term

D = Common difference

9 = F + 4D, 

-84 =F +31D, solve for F, D

F =205 / 9

D = - 31 / 9

23rd term =205/9 + (-31/9) * (23-1)

                  =205/9  -(31/9) *22

                  =205/9 - 682/9

                  = - 477 / 9

                  = - 53

The formula for the n^th term of an arithmetic sequence is:  t_n  =  t₁+ (n - 1)d

               t_n  =  n^th term               t₁  =  first term               d   =  common difference

fifth term = 9           --->      t₅  =  t₁ + (5 - 1)d       --->        9  =  t₁+ 4d

32^nd term = - 84     --->     t₃₂  =  t₁ + (32 - 1)d     --->     -84  =  t₁ + 31d

Subtracting the second equation from the first:  93  =  - 27d     --->     d  =  -93/27

Finding the value of t₁   --->     9  =  t₁+ 4d     --->     9  =  t₁ + 4(-93/27)     --->     t₁  =  205/9

t₂₃  =  205/9 + (23 - 1)(-93/27)     --->     t₂₃  =  205/9 + (22)(-93/27)  =  ........