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For how many positive integers x is 100<=x^2<=200

 Mar 21, 2020
 #1
avatar+1956 
+2

I think this will be easy to just list the ways.

 

x can be from 10^2 to 14^2,

 

Therefore, x can be 5 different integers.

 

Hope this helped!

 Mar 21, 2020
 #2
avatar+483 
+2

Let's look at the squares between 100 and 200.

First is obviously 100, which is equal to 102

\(100 = 10^2\)

\(121 = 11^2\)

\(144 = 12^2\)

\(169 = 13^2\)

\(196 = 14^2\)

\(15^2 = 225\), which would be too large, making our answer

square numbers inclusive between 100-200. 

 Mar 21, 2020
 #3
avatar+63 
+1

I got it but thank you though!

smallbrain  Mar 21, 2020

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