For how many positive integers x is 100<=x^2<=200
I think this will be easy to just list the ways.
x can be from 10^2 to 14^2,
Therefore, x can be 5 different integers.
Hope this helped!
Let's look at the squares between 100 and 200.
First is obviously 100, which is equal to 102
\(100 = 10^2\)
\(121 = 11^2\)
\(144 = 12^2\)
\(169 = 13^2\)
\(196 = 14^2\)
\(15^2 = 225\), which would be too large, making our answer
5 square numbers inclusive between 100-200.
I got it but thank you though!