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A standard six-sided die is rolled  times. You are told that among the rolls, there was one  two 's, and three 's. How many possible sequences of rolls could there have been? (For example,  is one possible sequence.)

 

I got 120, but it's wrong

Any Help? 

 Feb 5, 2021

3+0 Answers

 #1
avatar+79 
+1

360 and here is a link to the same prob

 

https://web2.0calc.com/questions/matematicas_47

 Feb 5, 2021
 #2
avatar+30 
+1

That is incorrect.

QueenOfAllTrades  Feb 5, 2021
 #3
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Is this what your example had? 1, 2, 2, 3, 3, 3. If that is the case, then all you do is to "permute" this combination into its permutations: Since you have 6 numbers, then the number of permutations=

 

6! / [3!2!1!] =720 /[6*2*1] =720 /12 ==60 permutations

 Feb 5, 2021

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