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Let ABCD be a trapezoid with bases BC and AD. In this trapezoid, the angle DBA is 105 degrees, with angle BAD is equal to 43 degrees. Finally, angle BCD is 141 degrees so what is angle CBD?

 Thank you in advance!!!

 Jul 23, 2020
edited by Guest  Jul 23, 2020
 #1
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In trapezoid ABCD, BC || AD, angle ABD =105°, angle A=43°, and angle C=141°. Find angle CBD, in degrees.

 

 

ok, the first thing I did is tried to work out what the trapezium looked like. 

THEN the answer became obvious.

BUT

it also became ovvious that I did not need to know what the trapezium looked like in ordet to answer this question.

 

Draw ANY trapezium where BC||AD

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 Jul 24, 2020
 #2
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Let ABCD be a trapezoid with bases BC and AD. In this trapezoid, the angle DBA is 105 degrees, with angle BAD is equal to 43 degrees. Finally, angle BCD is 141 degrees so what is angle CBD?

 

You can do it nowlaugh

 

 Jul 24, 2020
edited by Dragan  Jul 24, 2020
 #3
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Thank you for the diagram!!!

Guest Jul 24, 2020
 #4
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My pleasure!smiley

Dragan  Jul 25, 2020

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