Please help :)

In trapezoid ABCD, BC || AD, angle ABD =105°, angle A=43°, and angle C=141°. Find angle CBD, in degrees.

ok, the first thing I did is tried to work out what the trapezium looked like. 

THEN the answer became obvious.

BUT

it also became ovvious that I did not need to know what the trapezium looked like in ordet to answer this question.

Draw ANY trapezium where BC||AD

Label 

Label

Let ABCD be a trapezoid with bases BC and AD. In this trapezoid, the angle DBA is 105 degrees, with angle BAD is equal to 43 degrees. Finally, angle BCD is 141 degrees so what is angle CBD?

You can do it now