Find three consecutive odd numbers such that the sum of five times the smaller number and twicethe larger number is 33 more than six times the median number.
a=0;b=0;c=0;d=0;e=0;p=0; cycle:n= a*10000+b*1000+c*100+d*10+e;if(n%2==1 and n*5+2*(n+4)==6*(n+2)+33, goto loop, goto next); loop:printn,", ",;p=p+1; next:e++;if(e<10, goto cycle, 0);e=0;d++;if(d<10, goto cycle, 0);e=0;d=0;c++;if(c<10, goto cycle,0);c=0;d=0;e=0;b++;if(b<10, goto cycle,0);e=0;d=0;c=0;b=0;a++;if(a<10, goto cycle,0);print"Total = ",p
OUTPUT: Your numbers are: 37, 39, 41
