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Find g(x), with terms in order of decreasing degree, if we have that \(8x^4-7x^2+8x-7+g(x)=x + 1.\)

 Mar 21, 2020

Best Answer 

 #4
avatar+483 
+2

Sorry, I think I may have messed up my answer. The answer should be:

\(g(x) = -8x^4+7x^2-7x+8\)

So sorry for my mistake!(On subtraction too :P)

.
 Mar 21, 2020
edited by jfan17  Mar 21, 2020
 #1
avatar+1956 
+1

Hint:

 

We can move over the x+1 and leave the g(x) by itself. 

 Mar 21, 2020
 #2
avatar+483 
+1

Hey there qwerty! First, this is just some basic rearranging. We subtract on both sides, to get:

 

\(g(x) = x+ 1 -8x^4 +7x^2 -8x +7\)

Next, let's collect like terms and rearrange it in order of decreasing degree. What that means is that the highest "power" goes to the leftmost of the equation, with the lowest(the 0th power) degree going to the right. We then get:

 

\(g(x) = -8x^4+7x^2-7x+8\) as our final answer!

 Mar 21, 2020
edited by jfan17  Mar 21, 2020
 #3
avatar+389 
0

This wasn't correct

qwertyzz  Mar 21, 2020
 #4
avatar+483 
+2
Best Answer

Sorry, I think I may have messed up my answer. The answer should be:

\(g(x) = -8x^4+7x^2-7x+8\)

So sorry for my mistake!(On subtraction too :P)

jfan17 Mar 21, 2020
edited by jfan17  Mar 21, 2020

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