please help

You choose a rank for the three cards, then choose a rank for the two cards.  There are C(52,5) ways of choosing 5 cards, so the probability is

$$\frac{\binom{13}{2} \binom{4}{2} \binom{4}{3}}{\binom{52}{5}} = \frac{3}{4165}.$$

Guest’s answer is wrong. So it appears he didn’t learn it.

There are numerous examples of online poker-hand probability texts and examples. Google is a good starting point ...Bing is too.... so is Yahoo.... and Dogpile....

Solution for this question:

Choose the rank for the triple nCr(13,1)

Choose three suits for the triple nCr(4,3)

Choose a different rank for the pair nCr(12,1)

Choose two suits for the pair nCr(4,2)

Then

Divide this by the total number of five-card hands. nCr(52,5)

$\hspace {7cm} \large \text{ } \dfrac{\dbinom {13}{1}\dbinom {4}{3}\dbinom {12}{1}\dbinom {4}{2}}{\dbinom {52}{5}} = \dfrac{6}{4165} \approx 0.144\%$

GA