+0  
 
0
24
1
avatar

Yolanda throws a sphere up in the air from the top of a building. After tt seconds, the height of the sphere above the ground is hh feet, where h=−16t^2+40t+78.  After how many seconds does the sphere hit the ground?

 Oct 7, 2020
 #1
avatar
0

When the sphere hits the ground , h = 0

0 = -16t^2 + 40t+ 78        Use Quadratic Formula to solve for 't'   ....throw out negative values for 't'

 Oct 7, 2020

28 Online Users

avatar
avatar