Given positive integers x and y such that x not equal to y and 1/x + 1/y = 1/18, what is the smallest possible value for x + y?
1/x + 1/y = 1/18
x+yxy=118.
18x+18y=xy
xy−18x−18y=0
Note that the expression is very close to (x−18)(y−18) is if I add 324 to both sides.
(x−18)(y−18)=324.
324=2^2*3^4
12+18=30
27+18=45
30 and 45 give the largest result, thus x+y=30+45=75.
Since this is a symmetric equation (you can interchange x and y without changing the equation),
the minimum value will occur when x = y.
Solving 1/x + 1/y = 1/18 ---> 1/x + 1/x = 1/18 ---> 2/x = 1/18 ---> x = 36 ---> x + y = 72.
@geno3141, "x and y such that x not equal to y" in the problem.
Sorry; try the numbers close to this: 30 and 45.
Thank you! I somehow forgot to add 18 to both the numbers, 12 and 27.