+0  
 
0
80
4
avatar

A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?

 Jan 15, 2020
 #1
avatar
0

The shorrtest distance is 10 - 5*sqrt(2).

 Jan 15, 2020
 #2
avatar+109739 
+1

*****

 

 

cool cool cool

 Jan 15, 2020
edited by CPhill  Jan 15, 2020
 #3
avatar+11729 
+1

A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?

 

laugh

 Jan 15, 2020
 #4
avatar+22108 
+2

Distance from center to corner (vertice) = sqrt (5^2 + 5^2 + 5^2) = sqrt 75

 

distance from center to surface is 5

sqrt75 - 5 = 3.66 units

 Jan 15, 2020

27 Online Users

avatar
avatar