A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?
A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?

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Distance from center to corner (vertice) = sqrt (5^2 + 5^2 + 5^2) = sqrt 75
distance from center to surface is 5
sqrt75 - 5 = 3.66 units