A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?
A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?
Distance from center to corner (vertice) = sqrt (5^2 + 5^2 + 5^2) = sqrt 75
distance from center to surface is 5
sqrt75 - 5 = 3.66 units