+33 Thomas spent 4/11 of his money on 4 similar mangoes and 12 similar pears.
A pear cost 1/3 as much as a mango. Find the number of pears Thomas could
buy with the rest of his money.
Let the cost of 1 mango==M
Then the cost of 1 pear==1/3M
4M + 1/3M*12 ==4/11
8M ==4/11, solve for M
M ==1/22 - cost of 1 mango
Cost of 1 pear==1/3 * 1/22=1/66
1 - 4/11 ==7/11 of his money left
[7/11] / [1/66] ==[7/11 x 66] ==462 / 11==42 pears - he could buy with the rest of his money.
+237 Let total money = 1x
Let cost of one mango = M
pear = P
4x/11 = 4M + 12P -- (1)
P = 1/3M => M = 3P -- (2)
Put in (1) => 4(3P) + 12P = 4/11x
=> 12P + 12P = 4/11x => P = 4/24x 6 * 11
P = x/66 -- (3)
Money left => x = 4/11x = 7/11x Multiply by 7/11 both sides
7/11x = 7/11x * 66 6P = 42
Thomas can buy 42 pears with cost of his money
