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Thomas spent 4/11 of his money on 4 similar mangoes and 12 similar pears.

A pear cost 1/3 as much as a mango. Find the number of pears Thomas could

buy with the rest of his money.

 Feb 3, 2022
 #1
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+2

Let the cost of 1 mango==M
Then the cost of 1 pear==1/3M


4M  +  1/3M*12 ==4/11
8M ==4/11, solve for M


M ==1/22 - cost of 1 mango
Cost of 1 pear==1/3 * 1/22=1/66


1 - 4/11 ==7/11 of his money left
[7/11] / [1/66] ==[7/11 x 66] ==462 / 11==42 pears - he could buy with the rest of his money.

 Feb 3, 2022
 #2
avatar+138 
+4

Let total money = 1x

Let cost of one mango = M

                         pear = P

4x/11 = 4M + 12P -- (1)

P = 1/3M => M = 3P -- (2)

Put in (1) => 4(3P) + 12P = 4/11x

=> 12P + 12P = 4/11x => P = 4/24x 6 * 11

P = x/66 -- (3)

Money left => x = 4/11x = 7/11x Multiply by 7/11 both sides

7/11x = 7/11x * 66 6P = 42

Thomas can buy 42 pears with cost of his money

 Feb 4, 2022

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