how many ounces of a 12 alcohol solution must be mixed with 2 ounces of a 20% alcohol solution to make a 14% alcohol solution?
I assumed that 12 means 12% alcohol solution.
Let the number of ounces of 12% solution = T
0.12T + 0.2*2 =0.14*[T+2], solve for T
T = 6 ounces of 12% solution added to 2 ounces of 20% solution will make 8 ounces of 14% solution.
