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The image is of a cuboid with length, width and height as 12 inches,?5 inches?and?4 inches?respectively. The right vertical side is shaded.What is the surface area of the shoe box with the dimensions shown in the diagram? Use a net.

 May 1, 2020

Best Answer 

 #1
avatar+300 
+1

We can solve this problem by listing out the box's individual sides. There are 6 of them here.

 

Keep in mind that opposite sides have the same areas :D

 

There's one side, the side measuring 5 in. by 4 in. = 20 square inches. As there are two of those, they amount to a total of 40 square inches.

 

Then there's a lengthy rectangular side, measuring 12 in. by 4 in. = 48 square inches. Once again, there are two, so those two sides have 96 square inches total.

 

Then there's the bottom side, measuring 12 in. by 5 in. = 60 square inches. As the top and bottom are identical, those amount to 120 square inches total.

 

So, the total surface area of the shoebox will be 40 + 96 + 120 = 256 square inches :D

 May 1, 2020
 #1
avatar+300 
+1
Best Answer

We can solve this problem by listing out the box's individual sides. There are 6 of them here.

 

Keep in mind that opposite sides have the same areas :D

 

There's one side, the side measuring 5 in. by 4 in. = 20 square inches. As there are two of those, they amount to a total of 40 square inches.

 

Then there's a lengthy rectangular side, measuring 12 in. by 4 in. = 48 square inches. Once again, there are two, so those two sides have 96 square inches total.

 

Then there's the bottom side, measuring 12 in. by 5 in. = 60 square inches. As the top and bottom are identical, those amount to 120 square inches total.

 

So, the total surface area of the shoebox will be 40 + 96 + 120 = 256 square inches :D

CentsLord May 1, 2020
 #2
avatar+111329 
+1

THX, CentsLord....excellent    !!!

 

 

cool cool cool

CPhill  May 1, 2020
 #3
avatar+300 
+1

Thank you!

CentsLord  May 1, 2020

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