How many integer solutions exist for $x$ if $\frac12\le\frac x8\le\frac79$?
\(\frac12\le\frac x8\le\frac79\)
We commonize the denominator:
\(\frac{36}{72}\le\frac{9x}{72}\le\frac{56}{72}\)
This works out when x=4, 5, and 6
I hope this helped,
Gavin
Please don't just type in the answer, read the solution and try to understand the problem. Try to do other problems like this on your own. Then you can actually improve.