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avatar+264 

use the information provided to write the standard form equation of the circle

1. ends of a diameter: (11,-6) and (1,14)

use the information provided to write the genral conic form equation of each circle.

1. three points of the circle:

( 7,-4)(-3,-4) and ( 6,-7)

identify the centere and radius. then sketch the graph

1. x^2+y^2-4x-14=0

 Mar 23, 2020
 #1
avatar+111327 
+1

Here's a couple  :

 

1. If the  ends of a diameter  are  11,-6)  and (1,14)   then the  midpoint  is the  center of the circle

 

So   we  have that     [ (11 + 1) / 2  , (14 - 6)/2 ]  =  [ 12/2, 8/2 ]  = (6, 4)  is the  center

 

And  the  radius^2 can be computed as    [ ( 1 -6)^2  + (14 -4)^2 ] =   [ 5^2  + 10^2]  = 125

 

So...the  equation of the  circle  is

 

( x - 6)^2  + (y - 4)^2  =125

 

x^2  - 12x + 36  + y^2  - 8y  + 16   =   125

 

x^2  + y^2  - 12x  - 8y  - 73    = 0

 

 

cool cool cool

 Mar 23, 2020
 #2
avatar+1968 
+1

Nice, CPhill!

CalTheGreat  Mar 23, 2020
 #4
avatar+264 
0

Thank you!

xxJenny1213xx  Mar 23, 2020
 #3
avatar+111327 
+1

identify the centere and radius. then sketch the graph

1. x^2+y^2-4x-14=0

 

Cmplete the square on x   and  we have that

 

(x^2  -4x  + 4)  + y^2  =  14  + 4

 

(x - 2)^2  + (y - 0)^2  = 18

 

The center  is  ( 2, 0)

The radius  =  √18

 

 

cool cool cool

 Mar 23, 2020

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