Find the equation of the parabola that goes through the three points (0, 9), (1, 7) and (2, 7).
Find the equation of the parabola that goes through the three points (0, 9), (1, 7) and (2, 7).
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\(y=ax^2+bx+c\)
Put the coordinates of the three points in
the equation \(y=ax^2+bx+c\), and solve for a, b, and c.
I. \(9=c\)
II. \(7=a+b+9\)
III. \(7=4a+2b+9\)
4 * II . \(28=4a+4b+36\)
- III. \(\underline{7=4a+2b+9}\)
21 = 2b + 27
\(2b=21-27=-6\)
\(b=-3\)
\(7=a+b+9\)
\(7=a-3+9\)
\(a=1\)
The general equation \(y=ax^2+bx+c\)
becomes the real equation \(y=x^2-3x+9\).
!