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A football player punts a football at an inclination of 45 degrees to the horizontal at an initial velocity of

70 feet per second. The height of the football in feet is given by the quadratic function

h(x)= -32x^2/

           (70)^2  +x+4            WRITTEN LIKE THIS BELOW TOO if u were confused

 

h(x)= (-32x^2/(70)^2) +x+4

where x is the horizontal distance of the football from the point at which it was kicked. What was the horizontal distance of the football from the point at which it was kicked when the height of the ball is at a​ maximum? What is the maximum height of the​ football?

 

MAXIMUM??_____ MINIMUM???____

 Mar 10, 2020
 #1
avatar+25917 
+1

Maximum will occur at x = -b/2a =  1/ (2 ( 32/70^2)) =   4900/64 = x = 76.563 feet

 

Substitute this value of 'x' in to the h(x) equation to find the height at this point......

 Mar 10, 2020
 #2
avatar+318 
-1

GOT IT THANK U SO MUCH sorry

mharrigan920  Mar 11, 2020

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