+0

+1
140
7
+2448

$$6\sqrt[4]{567x^4}$$

$$4\sqrt[3]{64n^8}$$

Oct 23, 2018

#1
+2448
+1

Before you say anything, yes I did try. I still can't do it. My answers never seem to look correct. I only tried the first one.

Oct 23, 2018
#2
+2448
+1

What I got for the first one so far: $$6\sqrt[4]{3^4x^4}$$

RainbowPanda  Oct 23, 2018
#3
+5091
+2

$$6\sqrt[4]{567x^4} = \\ 6\sqrt[4]{3^4x^4\cdot 7} =\\ 6\cdot 3x\sqrt[4]{7} = \\ 18x\sqrt[4]{7}$$

$$4\sqrt[3]{64n^8} = \\ 4\sqrt[3]{2^6 n^6 \cdot n^2} = \\ 4\cdot 2^2 n^2 \sqrt[3]{n^2} = \\ 16n^2 \sqrt[3]{n^2}$$

.
Oct 23, 2018
edited by Rom  Oct 23, 2018
#4
+2448
0

Seems I would've done it the wrong way anyways, why is it that I have to multiply by 7?

RainbowPanda  Oct 23, 2018
#5
+5091
+1

$$567 = 81 \cdot 7 = 3^4 \cdot 7$$

Rom  Oct 23, 2018
#6
+2448
0

Oh I guess that makes sense

RainbowPanda  Oct 23, 2018
#7
+101044
0

It is very nice to see you interacting Panda but it would be nice to also see you say 'thanks' to Rom :)

Melody  Oct 24, 2018