+0  
 
+1
103
7
avatar+2442 

Radicals:

\(6\sqrt[4]{567x^4}\)

\(4\sqrt[3]{64n^8}\)

 Oct 23, 2018
 #1
avatar+2442 
+1

Before you say anything, yes I did try. I still can't do it. My answers never seem to look correct. I only tried the first one.

 Oct 23, 2018
 #2
avatar+2442 
+1

What I got for the first one so far: \(6\sqrt[4]{3^4x^4}\)

RainbowPanda  Oct 23, 2018
 #3
avatar+4449 
+2

 

\(6\sqrt[4]{567x^4} = \\ 6\sqrt[4]{3^4x^4\cdot 7} =\\ 6\cdot 3x\sqrt[4]{7} = \\ 18x\sqrt[4]{7}\)

 

\(4\sqrt[3]{64n^8} = \\ 4\sqrt[3]{2^6 n^6 \cdot n^2} = \\ 4\cdot 2^2 n^2 \sqrt[3]{n^2} = \\ 16n^2 \sqrt[3]{n^2}\)

.
 Oct 23, 2018
edited by Rom  Oct 23, 2018
 #4
avatar+2442 
0

Seems I would've done it the wrong way anyways, why is it that I have to multiply by 7?

RainbowPanda  Oct 23, 2018
 #5
avatar+4449 
+1

\(567 = 81 \cdot 7 = 3^4 \cdot 7\)

Rom  Oct 23, 2018
 #6
avatar+2442 
0

Oh I guess that makes sense

RainbowPanda  Oct 23, 2018
 #7
avatar+99327 
0

It is very nice to see you interacting Panda but it would be nice to also see you say 'thanks' to Rom :)

Melody  Oct 24, 2018

4 Online Users

avatar