+277 Thing 1 and Thing 2 were selling tickets to their upcoming play. They were two different types of tickets, adult and children. Thing 1 sold 3 adult tickets and 12 children's tickets for a total of $70. Thing 2 made $216 from the 12 adult and 12 children tickets it sold. What was the price of each type of ticket?
+128407 Let x be the price of the children's ticket and y be the price of the adult...so we have
12x + 3y = 70
12x + 12y = 216 subtract the first equation from the second...this gives
9y = 156 divide both sides by 9
y = $16.22 this is the approx cost of the adult ticket
And using the first equation to find the cost of the child's ticket, we have
12x + 3(16.22) = 70
12x + 48.66 = 70 subtract 48.66 from each side
12x = 21.34 divide both sides by 12
x = $1.78 and this is the cost of the child's ticket
+128407 Let x be the price of the children's ticket and y be the price of the adult...so we have
12x + 3y = 70
12x + 12y = 216 subtract the first equation from the second...this gives
9y = 156 divide both sides by 9
y = $16.22 this is the approx cost of the adult ticket
And using the first equation to find the cost of the child's ticket, we have
12x + 3(16.22) = 70
12x + 48.66 = 70 subtract 48.66 from each side
12x = 21.34 divide both sides by 12
x = $1.78 and this is the cost of the child's ticket
