Thing 1 and Thing 2 were selling tickets to their upcoming play. They were two different types of tickets, adult and children. Thing 1 sold 3 adult tickets and 12 children's tickets for a total of $70. Thing 2 made $216 from the 12 adult and 12 children tickets it sold. What was the price of each type of ticket?

AngelicaMarrufo
Mar 2, 2015

#1**+5 **

Let x be the price of the children's ticket and y be the price of the adult...so we have

12x + 3y = 70

12x + 12y = 216 subtract the first equation from the second...this gives

9y = 156 divide both sides by 9

y = $16.22 this is the approx cost of the adult ticket

And using the first equation to find the cost of the child's ticket, we have

12x + 3(16.22) = 70

12x + 48.66 = 70 subtract 48.66 from each side

12x = 21.34 divide both sides by 12

x = $1.78 and this is the cost of the child's ticket

CPhill
Mar 2, 2015

#1**+5 **

Best Answer

Let x be the price of the children's ticket and y be the price of the adult...so we have

12x + 3y = 70

12x + 12y = 216 subtract the first equation from the second...this gives

9y = 156 divide both sides by 9

y = $16.22 this is the approx cost of the adult ticket

And using the first equation to find the cost of the child's ticket, we have

12x + 3(16.22) = 70

12x + 48.66 = 70 subtract 48.66 from each side

12x = 21.34 divide both sides by 12

x = $1.78 and this is the cost of the child's ticket

CPhill
Mar 2, 2015