Suppose you drop a ball from a window 32 meters above the ground. The ball bounces to 80% of its previous height with each bounce. What is the total number of meters (rounded to the nearest tenth) the ball travels between the time it is dropped and the 10th bounce?
If every bounce is 80% of the previous height, and you have ten bounces, then multiply 32 by .8 (it equals 25.6) and each successive solution after by .8 until you reach ten solutions. Add all the solutions together to get the answer.
To start you off,
30(.8)=25.6
25.6(.8)= 20.48
etc.
