Karan has 8 more dimes than nickels in his pocket. In total, the coins in his pocket are worth 3.05. How many of each type of coin does he have. write and solve equation to determine the answer.
Let the number of nickels = x then.....the number of dimes = x + 8 and we have that.....
Number * quantity = total value ......so.....
.05x + .10(x + 8) = 3.05 multiply through by 100
5x + 10(x + 8) = 305 simplify
15x + 80 = 305 subtract 80 from both sides
15x = 225 divide both sides by 15
x = 15 = the number of nickels
x + 8 = 15 + 8 = 23 = number of dimes
Let the number of nickels = x then.....the number of dimes = x + 8 and we have that.....
Number * quantity = total value ......so.....
.05x + .10(x + 8) = 3.05 multiply through by 100
5x + 10(x + 8) = 305 simplify
15x + 80 = 305 subtract 80 from both sides
15x = 225 divide both sides by 15
x = 15 = the number of nickels
x + 8 = 15 + 8 = 23 = number of dimes