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Karan has 8 more dimes than nickels in his pocket. In total, the coins in his pocket are worth 3.05. How many of each type of coin does he have. write and solve equation to determine the answer.

 Jan 27, 2016

Best Answer 

 #1
avatar+129847 
+10

Let the number of nickels = x    then.....the number of dimes = x + 8   and we have that.....

 

Number * quantity  = total value  ......so.....

 

.05x +  .10(x + 8)  = 3.05        multiply through by 100

 

5x  + 10(x + 8)  = 305    simplify

 

15x + 80   = 305      subtract 80 from both sides

 

15x = 225     divide both sides by 15

 

x = 15    =  the number  of nickels

 

x + 8   =  15 + 8 =  23   = number of dimes

 

 

 

cool cool cool

 Jan 27, 2016
 #1
avatar+129847 
+10
Best Answer

Let the number of nickels = x    then.....the number of dimes = x + 8   and we have that.....

 

Number * quantity  = total value  ......so.....

 

.05x +  .10(x + 8)  = 3.05        multiply through by 100

 

5x  + 10(x + 8)  = 305    simplify

 

15x + 80   = 305      subtract 80 from both sides

 

15x = 225     divide both sides by 15

 

x = 15    =  the number  of nickels

 

x + 8   =  15 + 8 =  23   = number of dimes

 

 

 

cool cool cool

CPhill Jan 27, 2016

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