+0  
 
0
44
2
avatar+12 

1. The vertex of a parabola is at (12, -4), and its axis of symmetry is vertical. One of the x-intercepts is at (15, 0). What is the x-coordinate of the other x-intercept

 

2. The graph of the equation \(y =ax^2 + bx + c \), where a, b, and c are constants, is a parabola with an axis of symmetry \(x = -3\). Find \(\frac{b}{a}\).

 Jan 27, 2021
 #1
avatar
+1

The vertex defines tha axis of symmetry as   x = 12

    the other x-intercept will be the same distance from the vertex as the one given....only on the OTHER side of the vertex

               x = 9  

 Jan 27, 2021
 #2
avatar
+1

The vertex value of x will be given by    - b/2a     this will be the axis of symmetry 

    -b/2a = -3

     b/a = 6

 Jan 27, 2021

56 Online Users

avatar
avatar
avatar