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# pls help. 2 questions

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1. The vertex of a parabola is at (12, -4), and its axis of symmetry is vertical. One of the x-intercepts is at (15, 0). What is the x-coordinate of the other x-intercept

2. The graph of the equation $$y =ax^2 + bx + c$$, where a, b, and c are constants, is a parabola with an axis of symmetry $$x = -3$$. Find $$\frac{b}{a}$$.

Jan 27, 2021

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The vertex defines tha axis of symmetry as   x = 12

the other x-intercept will be the same distance from the vertex as the one given....only on the OTHER side of the vertex

x = 9

Jan 27, 2021
#2
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The vertex value of x will be given by    - b/2a     this will be the axis of symmetry

-b/2a = -3

b/a = 6

Jan 27, 2021