The polynomial p(x)=x2+ax+b has distinct roots 2a and 2b. Find a+b.
By Vieta's, we have:
−a=2a+2b (i)
b=4ab (ii)
From the second equation, we have a=14.
Subbing this into (i) gives us b=−38
Thus, a+b=14−38=−18
omg! nicely done! thx a lot!
No worries!!!