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An ordinary $6$-sided die has a number on each face from $1$ to $6$ (each number appears on one face). How many ways can I paint two faces of a die blue, so that the product of the numbers on the painted faces isn't equal to $6$?

 

pls help asap

nvm it's 13

 Jan 6, 2021
edited by Guest  Jan 6, 2021
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There are 6choose2 or 15 ways to paint two faces. There are two ways to get a product of 6. (6,1) and (3,2). 15-2=13

:D

 Jan 7, 2021

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