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0
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avatar+108 

Let 

 

        \(f(n) = \left\{ \begin{array}{cl} n^3+2n-1 &\text{ if }n>1, \\ n-1 &\text{ if }n \le 1. \end{array} \right.\)

 

Find \(f(0)+f(1)+f(2).\)

 Sep 7, 2020
 #2
avatar+31103 
+4

n = 0

n< 1 so f(0) = n-1 or f(0) = -1

 

n = 1 so f(1) = n-1 or f(1) = 0

 

n = 2

n>1 so f(2) = n^3 + 2n -1 or f(2) = 2^3 + 2*2 - 1  so f(2) = 11

 

I'll let you add them up..

 Sep 7, 2020

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